Figure 1
One motion, three disguises. The rule never touches the coefficient, and the only work it demands is the rewriting that turns a radical or a reciprocal into a bare power of .
Reviewed by ACEpath AP Math Editorial Team
Last Updated: September 2026
30-second summary
The power rule replaces the definition of the derivative for every term of the form xn. Bring the exponent down as a multiplier, then subtract one from it: dxdxn=nxn−1. The rule is not restricted to positive whole numbers. A radical is a fractional exponent, a reciprocal is a negative exponent, and a constant term is the case n=0, which correctly produces zero. What the rule does not touch is the coefficient, which travels along unchanged. Nearly every error in this topic happens before the rule is applied, when a square root or a fraction is left in its original shape and the exponent never gets isolated. Rewrite first, differentiate second.
This rule is a tool rather than a topic. It is scored inside larger questions, usually as the first step of a tangent line, a rate of change, or a critical point, and a slip here contaminates every later part of the answer. The grader awards the derivative expression itself, so the points for this skill are collected or lost in a single line of work.
One motion, three disguises. The rule never touches the coefficient, and the only work it demands is the rewriting that turns a radical or a reciprocal into a bare power of x.
| Written in the problem | Power form | Derivative |
|---|---|---|
| x | x1/2 | 21x−1/2 |
| x31 | x−3 | −3x−4 |
| 3x1 | x−1/3 | −31x−4/3 |
| 7 | 7x0 | 0 |
The exponent is the only thing that changes. A coefficient in front of the power stays in front, so 5x4 becomes 20x3 and 41x8 becomes 2x7. A constant term follows the same rule with n=0, which gives 0⋅x−1=0; that is why constants vanish rather than becoming x−1.
For a positive integer n, expand the difference quotient:
h(x+h)n−xn=hxn+nxn−1h+(2n)xn−2h2+⋯−xn=nxn−1+(2n)xn−2h+⋯
Every term after the first carries a factor of h, so the limit as h→0 leaves only nxn−1. The argument explains the shape of the result rather than just the result: exactly one term survives the division, the one whose h cancels, and its coefficient is the number of ways to pick a single h from n factors.
| Expression | Rule to use | Why |
|---|---|---|
| 3x | Exponential rule | The variable sits in the exponent, not the base |
| xx | Neither rule alone | Both base and exponent move |
| sin2x | Chain rule | The power sits outside a function of x |
| ∣x∣ | None at the origin | There is no exponent to bring down |
The test is mechanical: the rule applies when the base is a bare x and the exponent is a constant. If either condition fails, the expression needs a different tool, and the power rule applied anyway will produce a wrong answer that looks plausible.
Borrowed idea: The power rule is a single motion repeated: bring the exponent down in front, then drop that exponent by one. Nothing else moves. A coefficient travels along untouched, because scaling a function scales its slope by the same factor. The rule survives every disguise the exam can apply, since a radical is a fractional exponent, a reciprocal is a negative exponent, and a lone constant is the case n=0. Almost every lost point comes from a rewriting mistake made before the rule was applied, not from the rule itself, which means the skill actually being tested is converting the expression into power form before the differentiating begins.
| Exam disguise | What you see on the page | What your brain must translate | Required execution |
|---|---|---|---|
| A radical | x or 4x3 | Fractional exponents | Write x1/2 or x3/4 first |
| A fraction with x below | x25 | A negative exponent with a coefficient | Rewrite as 5x−2 |
| A constant | 9 | The case n=0 | Differentiate to 0, not to 9 |
| A tangent-line request | "the slope of the line tangent to f at x=4" | A derivative evaluated at one input | Differentiate, then substitute |
① Take f(x)=3x−x2+5 and write it as 3x1/2−2x−1+5x0 before differentiating. Compare the two versions on the page and notice that the second one has no decision left to make.
② Build a table of five expressions your teacher has used that are not in power form, and convert each one. The conversion is the whole skill, and it takes about a minute to practise.
③ On any tangent-line question, differentiate first and substitute second, never the other way around. Substituting early produces a number with no slope attached to it.
Core Archetype (Simplest Form): Find dxd(4x3−x26+x).
Standard Execution:
- Convert. The expression becomes 4x3−6x−2+x1/2.
- Differentiate each term. 12x2, then 12x−3, then 21x−1/2.
- Watch the signs. Subtracting 6x−2 produces +12x−3, because the exponent is negative.
- Assemble. The derivative is 12x2+12x−3+21x−1/2.
- Stop. Simplification is optional unless a later part asks for a value.
Exam Variation (Context / Parameter Shift): The curve y=x3−6x2+9x has two points where the tangent is horizontal. Find them.
Solution: Differentiate to get y′=3x2−12x+9=3(x−1)(x−3). A horizontal tangent requires y′=0, so x=1 or x=3. Substituting gives the points (1,4) and (3,0). The derivative answers the question and the original function supplies the heights, which is why both must be kept on the page.
Common Traps & Failure Signals:
6D Cognitive Error Diagnosis (Where Your Thinking Broke):
MCQ 1
If f(x)=6x, what is f′(9)?
MCQ 2
What is the derivative of g(x)=x28?
MCQ 3
Let h(x)=5x4−12. What is h′(x)?
FRQ 4
Let f be the function defined by f(x)=2x3−9x2+12x−4 for all real x.
(a) Find f′(x).
(b) Find the x-coordinates of all points on the graph of f where the tangent line is horizontal.
(c) Write an equation for the line tangent to the graph of f at x=1.
(d) The function g is defined by g(x)=xf(x) for x=0. Find g′(x) and evaluate g′(2).
| Move | |
|---|---|
| xn with n constant | nxn−1 |
| Coefficient in front | Multiply it, do not change it |
| Radical | Rewrite as a fractional exponent |
| Variable in a denominator | Rewrite as a negative exponent |
| Constant alone | Derivative is 0 |
| Variable in the exponent | Stop: this needs the exponential rule |
Strengthen this topic with AP-style practice, or continue to next topic.
Reviewed by ACEpath AP Math Editorial Team
Last Updated: September 2026
30-second summary
The power rule replaces the definition of the derivative for every term of the form xn. Bring the exponent down as a multiplier, then subtract one from it: dxdxn=nxn−1. The rule is not restricted to positive whole numbers. A radical is a fractional exponent, a reciprocal is a negative exponent, and a constant term is the case n=0, which correctly produces zero. What the rule does not touch is the coefficient, which travels along unchanged. Nearly every error in this topic happens before the rule is applied, when a square root or a fraction is left in its original shape and the exponent never gets isolated. Rewrite first, differentiate second.
This rule is a tool rather than a topic. It is scored inside larger questions, usually as the first step of a tangent line, a rate of change, or a critical point, and a slip here contaminates every later part of the answer. The grader awards the derivative expression itself, so the points for this skill are collected or lost in a single line of work.
One motion, three disguises. The rule never touches the coefficient, and the only work it demands is the rewriting that turns a radical or a reciprocal into a bare power of x.
| Written in the problem | Power form | Derivative |
|---|---|---|
| x | x1/2 | 21x−1/2 |
| x31 | x−3 | −3x−4 |
| 3x1 | x−1/3 | −31x−4/3 |
| 7 | 7x0 | 0 |
The exponent is the only thing that changes. A coefficient in front of the power stays in front, so 5x4 becomes 20x3 and 41x8 becomes 2x7. A constant term follows the same rule with n=0, which gives 0⋅x−1=0; that is why constants vanish rather than becoming x−1.
For a positive integer n, expand the difference quotient:
h(x+h)n−xn=hxn+nxn−1h+(2n)xn−2h2+⋯−xn=nxn−1+(2n)xn−2h+⋯
Every term after the first carries a factor of h, so the limit as h→0 leaves only nxn−1. The argument explains the shape of the result rather than just the result: exactly one term survives the division, the one whose h cancels, and its coefficient is the number of ways to pick a single h from n factors.
| Expression | Rule to use | Why |
|---|---|---|
| 3x | Exponential rule | The variable sits in the exponent, not the base |
| xx | Neither rule alone | Both base and exponent move |
| sin2x | Chain rule | The power sits outside a function of x |
| ∣x∣ | None at the origin | There is no exponent to bring down |
The test is mechanical: the rule applies when the base is a bare x and the exponent is a constant. If either condition fails, the expression needs a different tool, and the power rule applied anyway will produce a wrong answer that looks plausible.
Borrowed idea: The power rule is a single motion repeated: bring the exponent down in front, then drop that exponent by one. Nothing else moves. A coefficient travels along untouched, because scaling a function scales its slope by the same factor. The rule survives every disguise the exam can apply, since a radical is a fractional exponent, a reciprocal is a negative exponent, and a lone constant is the case n=0. Almost every lost point comes from a rewriting mistake made before the rule was applied, not from the rule itself, which means the skill actually being tested is converting the expression into power form before the differentiating begins.
| Exam disguise | What you see on the page | What your brain must translate | Required execution |
|---|---|---|---|
| A radical | x or 4x3 | Fractional exponents | Write x1/2 or x3/4 first |
| A fraction with x below | x25 | A negative exponent with a coefficient | Rewrite as 5x−2 |
| A constant | 9 | The case n=0 | Differentiate to 0, not to 9 |
| A tangent-line request | "the slope of the line tangent to f at x=4" | A derivative evaluated at one input | Differentiate, then substitute |
① Take f(x)=3x−x2+5 and write it as 3x1/2−2x−1+5x0 before differentiating. Compare the two versions on the page and notice that the second one has no decision left to make.
② Build a table of five expressions your teacher has used that are not in power form, and convert each one. The conversion is the whole skill, and it takes about a minute to practise.
③ On any tangent-line question, differentiate first and substitute second, never the other way around. Substituting early produces a number with no slope attached to it.
Core Archetype (Simplest Form): Find dxd(4x3−x26+x).
Standard Execution:
- Convert. The expression becomes 4x3−6x−2+x1/2.
- Differentiate each term. 12x2, then 12x−3, then 21x−1/2.
- Watch the signs. Subtracting 6x−2 produces +12x−3, because the exponent is negative.
- Assemble. The derivative is 12x2+12x−3+21x−1/2.
- Stop. Simplification is optional unless a later part asks for a value.
Exam Variation (Context / Parameter Shift): The curve y=x3−6x2+9x has two points where the tangent is horizontal. Find them.
Solution: Differentiate to get y′=3x2−12x+9=3(x−1)(x−3). A horizontal tangent requires y′=0, so x=1 or x=3. Substituting gives the points (1,4) and (3,0). The derivative answers the question and the original function supplies the heights, which is why both must be kept on the page.
Common Traps & Failure Signals:
6D Cognitive Error Diagnosis (Where Your Thinking Broke):
MCQ 1
If f(x)=6x, what is f′(9)?
MCQ 2
What is the derivative of g(x)=x28?
MCQ 3
Let h(x)=5x4−12. What is h′(x)?
FRQ 4
Let f be the function defined by f(x)=2x3−9x2+12x−4 for all real x.
(a) Find f′(x).
(b) Find the x-coordinates of all points on the graph of f where the tangent line is horizontal.
(c) Write an equation for the line tangent to the graph of f at x=1.
(d) The function g is defined by g(x)=xf(x) for x=0. Find g′(x) and evaluate g′(2).
| Move | |
|---|---|
| xn with n constant | nxn−1 |
| Coefficient in front | Multiply it, do not change it |
| Radical | Rewrite as a fractional exponent |
| Variable in a denominator | Rewrite as a negative exponent |
| Constant alone | Derivative is 0 |
| Variable in the exponent | Stop: this needs the exponential rule |
Strengthen this topic with AP-style practice, or continue to next topic.